Please Login to access more options.
Problem 31 ($R/A$ Is A Field Iff $A$ Is Maximal)
Let $R$ be a commutative ring with unity, and let $A$ be a proper ideal of $R$. Prove that the following are equivalent.
- $R/A$ is a field.
- Whenever $B$ is an ideal of $R$ and $A\subseteq B\subseteq R$, then either $B=A$ or $B=R$. (We say that $A$ is a maximal ideal.)
The following pages link to this page.