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Announcements

Hot-Chocolate Break Room

  • Looking for SDL partners, or hoping to find a study group?
  • Share anything with the class. This is one place you can share SDL's.

Self-Directed Learning Projects

  1. Have a specific plan that helps you develop deeper understanding. Think about Bloom's Taxonomy (see 1 and 2), and focus your efforts towards the highest levels.
  2. Carry out the plan, making modifications as needed (follow new leads, keep in the time constraints, etc.).
  3. Create something based on what you learned (Bloom's taxonomy).
  4. Share your work publicly.
  5. Complete a short steward report to reflect on your learning process.

Brain Gains

  • Compute the derivative of the following functions:
  1. $f(x) = \pi^2$
  2. $\displaystyle g(x) = \frac{22}{7} x $
  3. $p(x) = x^3-2x^2+x+5$

Answer:

  1. $\displaystyle \frac{df}{dx} = 0$
  2. $\displaystyle g'(x) = \frac{22}{7}$
  3. $p'(x) = 3x^2-4x+1$

Where can I go for practice if my derivative skills are lacking? Thomas's calculus sections 3.3-3.6 are a great place to practice. You can use any calc text, if you had calculus at another school. In OpenStax, sections 3.3 - 3.6 are also a great place. https://openstax.org/books/calculus-volume-1/pages/3-3-differentiation-rules

  • If a rover's motion on flat ground is described by $(x,y)=(3,4)t+(-2,5)$, what is its speed? Assume $x$ and $y$ are measured in meters and $t$ is given in minutes. (Hint: the rover's speed is constant in this situation.)

Answer:

When $t=0$, $(x,y) = (-2,5)$. When $t=1$, it is at $(1,9)$, so its position has changed by $\Delta x = 3$ and $\Delta y=4$. This means the rover has moved a total of $\sqrt{3^2+4^2}=5$ meters, so its speed is 5 meters/minute.

If we haven't had someone present 1.2 yet, let's do that now.

  • Using the vectors on the screen, draw $\vec u+\vec v$ and $\vec u-\vec v$.

Answer:

We'll discuss this one.

If we haven't had someone present 1.6 yet, we'll have them share their work here.

  • Give the component form of a vector of length 2 that is parallel to $\left<3,4\right>$.

Answer:

A unit vector is $\frac{1}{5}(3,4)$, so the desired vector is twice this, namely $$\frac{2}{5}(3,4) = \left(\frac{6}{5},\frac{8}{5}\right).$$

If we haven't had someone present 1.8 yet, we'll do that here.

  • Draw and shade the region in space satisfying $0\leq z\leq 5$ with $x=2$.

Answer:

The region is an infinitely long sheet with $0\leq z\leq 5$, located 2 units out on $x$-axis, with the $y$ value taking on all possible values. The most common error here is to not let $y$ take on all possible values, in which case you'll end up with a short line segment at $y=0$ and $x=2$ running from 0 to 5 in the $z$ direction.

If we haven't had someone present 1.5 yet, we'll do that here.

Group Problems

Remember to pass the chalk between each problem.

  1. Give the component form of a vector that points from $(1,2,3)$ to $(-2,4,9)$.
  2. Give a vector equation of the line that passes through the point $(1,2,3)$ and $(-2,4,9)$ (all distances are in meters).
  3. An object starts at $P=(1,2,3)$ and each unit of time its displacement is $\vec v=(-4,5,1)$. Give an equation for the position $(x,y,z)$ at any time $t$.
  4. What is the speed of an object that follows the path described above?
  5. Use the law of cosines ($c^2=a^2+b^2-2ab\cos\theta$) to find the angle between the vectors $(-2,1)$ and $(1,3)$.
  6. Use the law of cosines to find the angle between the vectors $(1,2,3)$ and $(-2,4,9)$.

Problem Set
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