Presentations
6.10+Finals week plans
- For those who have not yet reached 80% mastery on the quizzes, there will be three more attempts for you to reach this benchmark.
- Quiz 13 occurs on Friday of week 13.
- Quiz 14A occurs on the last day of classes, which is Tuesday April 7, 2026.
- Quiz 14B occurs during our course's scheduled final exam time, which is Wed April 8 at 10:30 AM – 1:45 PM.
Pacing Tracker
- The quizzes have included questions for 28 objectives. How many have you passed? What are your plans to master those that you haven't mastered yet?
- Once you've passed 26 objectives, you have hit 80% of the total objectives (needed to pass the class with a grade of A/B/C).
- We've finished units 1 through 5. Have you started your self-directed learning project for each unit?
- The 6th project can be over any topic from the entire semester. Feel free to get started on this one as soon as you have an idea.
- Remember you can submit only one SDL project per week. Plan ahead and don't let yourself get behind.

Brain Gains
- Consider the surface $\vec r(u,v) = (u\cos v,u\sin v,9-u^2)$ for $0\leq v\leq 2\pi$ and $0\leq u\leq 3$.
- Draw the surface.
- Compute the differential $d\vec r$.
- The vector $\frac{\partial \vec r}{\partial u}du$ is a short (assuming $du$ is small) tangent vector to the surface. Compute $\ds \left|\frac{\partial \vec r}{\partial u}du \times \frac{\partial \vec r}{\partial v}dv\right|$.
- Give a physical interpretation of $\left|\vec r_u \times \vec r_v\right|dudv$.
- Set up an iterated integral to give the surface area of the surface above.
- Set up an integral to give the $z$-coordinate of the centroid of the surface.
- Let $\vec F = (-5y,5x)$.
- Set up a single integral to give the work done by $\vec F$ to go once counter-clockwise along the circle $\vec r(t) = (3\cos t, 3\sin t)$.
- Does $\vec F$ have a potential?
- For a vector field $\vec F(x,y)=(M,N)$ that is continuously differentiable everywhere, Green's theorem states $$\oint_C Mdx+Ndy = \iint_R N_x-M_ydA,$$ where $R$ is region inside a simple closed piecewise smooth curve $C$ that traverses around the boundary of $R$ in a counterclockwise fashion. Set up the double integral that gives the same result as the single integral we already set up.
Group Discussion
- Draw each curve or surface given below.
- $\vec r(t) = (3\cos t,3\sin t,4t)$ for $0\leq t\leq 6\pi$. (Check: Helix)
- $\vec r(u,v) = (u\cos v,u\sin v,v)$ for $0\leq v\leq 6\pi$ and $2\leq u\leq 4$. (Check: Spiral stair case)
- $\vec r(u,v) = (u\cos v,u\sin v,u)$ for $0\leq v\leq 2\pi$ and $0\leq u\leq 4$. (Check: Cone)
- For the cone in part c., compute $\left|\vec r_u \times \vec r_v\right|$ and then set up an iterated integral that would give the surface area of the cone.
- Let $\vec F = (5y,5x)$.
- Find a potential for $\vec F$, or explain why none exists.
- Compute the work done by $\vec F$ to go once counter-clockwise along the circle $\vec r(t) = (3\cos t, 3\sin t)$.
- Compute the derivative of each vector field $\vec F$ below (obtaining a square matrix). Then find a potential for $\vec F$ or explain why the vector field has no potential.
- $\vec F = (2x,3y)$ [Check: $D\vec F = \begin{bmatrix}2&0\\0&3\end{bmatrix}$ and $f = x^2+\frac{3}{2}y^2$ yields $\vec \nabla f = (2x,3y)$. We can quickly verify that $\vec\nabla f = \vec F$ by a direct computation. ]
- $\vec F = (2y,3x)$
- $\vec F = (3y,3x)$
- $\vec F = (4x,5y,6z)$
- $\vec F = (4x,5z,6y)$
- $\vec F = (4x,5z,5y)$
- $\vec F = (y^2+2x,2xy)$
- $\vec F = (x+yz,xz+4yz,xy+2y^2)$
- $\vec F = (x+yz,4yz,xy+2y^2)$
- $\vec F = (x+yz,xz+4yz,xy)$
- $\vec F = (yz,xz+4yz,xy+2y^2)$
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