- Consider the integral $\ds \int_{y=1}^{y=4}\left(\int_{x=-2}^{x=3}dx\right)dy$.
- Shade the region describe by the inequalities $1\leq y\leq 4$ and $-2\leq x\leq 3$.
- Compute the double integral.
- Consider the integral $\ds \int_{x=0}^{x=3}\int_{y=0}^{y=x}dydx$.
- Shade the region describe by the bounds of the integral.
- Compute the double integral.
- Compute the integral $\ds \int_{y=0}^{y=x}\int_{x=0}^{x=3}dxdy$. Why do you not get a number?
- Use a double integral to compute the area of the region between the curves $y=x^2$ and $y=x+2$.
- Write $\int_1^3 \sqrt{x} + x \, dx$ as a double integral $\int \int dy \, dx$
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